3.
a)
Here we have to find whether M enters q on w,
So let us assume q as the halting state of M, now we can reduce L to Halting problem of turing machine( i.e language HALTTM).
let us design a turing machine M1 such that:
1. on input <M,w> if M halts on w, then M1 enters enters q on input w
2. on input <M,w> if M does not halt on w, then M1 does not enter q on input w
And as we know halting problem is undecidable, so L also undecidable.
b)
here from the above design of M1 we can define
1. on input <M,w> if M halts on w, then M1 enters enters q on input w
2. on input <M,w> if M does not halt on w, then M1 does not enter q on input w and ends in looping.
So L is not Turing decidable, but turing recognizable.
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