Question

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The accompanying equency distribution represents the square footage of a random sample of 500 houses that are owner occupied year round Approximate the mean and standard deviation square footage IT Click the icon to view the data table The mean square footage is x = 2.462 (Round to the nearest Integer as needed) The standard deviation square footage is (Round to one decimal place as needed.) Housing Data Frequency Square footage 0 - 499 500 - 999 1000 - 1,499 1500 - 1,999 2,000 - 2.499 2,500 - 2.999 3,000 -3,499 3.500 - 3,999 4,000 -4,499 4,500 - 4999 Enter your answer in the answer box and then click Check Answd

Answer 1

Solution: Class Мf (M - X2 | Midpoint Frequency M 249.5 5 749.5 | 17 1249.5 33 1749.5 121 2249.5 119 2749.5 83 3249.5 45 3749.5 4249.5 26 4749.5 10 f = 500 0-499 500-999 1000-1499 1500-1999 2000-2499 2500-2999 3000-3499 3500-3999 4000-4499 4500-4999 Total 1247.5 12741.5 41233.5 211689.5 267690.5 4804864 2862864 1420864 478864 36864 94864 652864 1710864 3268864 5326864 (M – 7)2 xf 24024320 48668688 46888512 57942544 4386816 7873712 29378880 70145424 84990464 53268640 (M – 1)2 xf = 427568000 228208.5 41 146227.5 153729.5 110487 47495 Mf = 1220750 Mean square footage: Mf 1220750 -= 2441.5 500 x = 2442 Standard deviation square footage: 2(M — )2 x f 427568000 -= 925.7 Ef-1 500 - 1 S =