Question

Consider the octahedral complex [Co(NH3)5(NO2)]Cl2 (assume Δ/B = 2.5)

Part A: Which Tanabe-Sugano diagram applies to complexes of this type? Why?

Part B: Use the appropriate Tanabe-Sugano diagram to determine if the complex is high spin or low spin. Justify your answer.

Part C: Use the Tanabe Sugano diagram to determine the subcomponent ground term and spin allowed excited states for this octahedral complex.

Answer 1

Part A. In [co (NH3), (NO₂Cl2, metal co is in +3 oxidation number and the ligands NH₃ and NO₂ are strong ligands which can pair up the e's of metal. so formed complex is how spin Cost = do . So, do low spin Tanabe sugano diagram applies to this type of complex. Part B. Tanabe- Sugano diagram contains the vertical line at specific value of Dq|B. complexes lies in the left side of this vertical line have lower Dq|B value are high spin and those on the right have higher Dq 1B value are low spin cost de, low spin For this complex Dg 1B value is high, so it will lie on the right side of vertical line. Hence, low spin complex.

Partc! - Ground state teem is 'Aig spin - allowed transistions Tag 'Ang (Furest spin allowed Transition) 'Tig 'Aig (second spin allowed Transition) Vou