def plusThetaeigenket(theta):
return np.array([np.cos(theta/2),np.sin(theta/2)])
print("|+theta> = ",plusThetaeigenket,"\n")
def minusThetaeigenket(theta):
return np.array([-np.sin(theta/2),np.cos(theta/2)])
print("|-theta> = ",minusThetaeigenket,"\n")
Can you please help to solve where this python code went wrong for display the correct eigen ket value for theta? Thank you
Homework Answers
Hello,
In function call we need to pass the arguments through which it
is calling
Since you have not passed any argument during the function call, It
is just printing the address of the function rather than calling
and processing it
In this
first you need to initiate or take input from the user
for now i am initiating the value by 30.5
t1=30.5
t2=30.5
import numpy as np
def plusThetaeigenket(theta):
return
np.array([np.cos(theta/2),np.sin(theta/2)])
print("|+theta> = ",plusThetaeigenket(t1),"\n")
def minusThetaeigenket(theta):
return
np.array([-np.sin(theta/2),np.cos(theta/2)])
print("|-theta> = ",minusThetaeigenket(t2),"\n")
You will get output:
('|+theta> = ', array([-0.89695484, 0.44212217]), '\n')
('|-theta> = ', array([-0.44212217, -0.89695484]), '\n')
Comment for any doubt
thanks
Add Answer to:
def plusThetaeigenket(theta):
return np.array([np.cos(theta/2),np.sin(theta/2)])
print("|+theta> = ",plusThetaeigenket,"\n")
def minusThetaeigenket(theta):
return np.array([-np.sin(theta/2),np.cos(theta/2)])
print("|-theta> = ",minusThetaeigenket,"\
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