Null hypothesis: Ho :Opinion and Party Affiliation are independent
Alternate hypothesis: Ha :Opinion and Party Affiliation are dependent
degree of freedom(df) =(rows-1)*(columns-1)= | 4 | ||
for 4 df and 0.05 level of signifcance critical region χ2= | 9.488 | ||
Applying chi square test of independence: |
Expected | Ei=row total*column total/grand total | Approve | Disapprove | No opinion | Total |
Republican | 38.7600 | 22.8000 | 14.4400 | 76 | |
Democrat | 46.9200 | 27.6000 | 17.4800 | 92 | |
Independent | 16.3200 | 9.6000 | 6.0800 | 32 | |
total | 102 | 60 | 38 | 200 | |
chi square χ2 | =(Oi-Ei)2/Ei | Approve | Disapprove | No opinion | Total |
Republican | 0.2708 | 0.3439 | 0.0134 | 0.6281 | |
Democrat | 0.2022 | 0.4696 | 0.0155 | 0.6872 | |
Independent | 2.4475 | 4.2667 | 0.0011 | 6.7152 | |
total | 2.9205 | 5.0801 | 0.0299 | 8.0305 | |
test statistic X2 = | 8.0305 |
since test statistic does not falls in rejection region we fail to reject null hypothesis |
we do not have have sufficient evidence to conclude that :Opinion and Party Affiliation are dependent at 0.05 level of significance |
Classwork 12.2 Test for Independence and Homogeneity of Proportion 1. The contingency table below shows the...
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