MATLAB
When monochromatic light passes through a narrow slit it produces on a screen a diffraction pattern consisting of bright and dark fringes. The intensity of the bright fringes, I, as a function of can be calculated by:
where
Where is the light wave length and a is the width of the slit. Plot the relative intenstiy I / Imax as a function of for -20o <= <= 20o. Make one plot that contains three graphs for the cases
a = 10, a = 5, and a = . Label the axes, and display a legend.
MATLAB When monochromatic light passes through a narrow slit it produces on a screen a diffraction...
When monochromatic light passes through a narrow slit it produces on a screen a diffraction pattern consisting of bright and dark fringes. The intensity of the bright fringes, I, as a function of can be calculated by: where Where is the light wave length and a is the width of the slit. Plot the relative intenstiy I / Imax as a function of for -20o <= <= 20o. Make one plot that contains three graphs for the cases a =...
Please solve and plot using MATLAB: Please solve and plot with MATLAB: Thank you A monochromatic light that passes through a Incident slit produces on a screen a diffraction pattern light consisting of bright and dark fringes. The intensity of the bright fringes, I, as a function of 0 can be calculated by: πα where a asin θ , λ is the light wave length, a is the width of the slits. Make a 3-D plot (shown) that shows the...
MATLAB , chapter 5 figure(n) Create new figure i# window, 3130%) When monochromatic light passes through a narrow slit it produces on a sCreen a diffraction pattern consisting of bright and dark fringes. The intensity of the bright fringes, I. as a fimc- tion of e can be calculated by Incident light sin c 2 where a TUCI sin e ax where A is the light wave length and a is the width of the slit. Plot the relative intensity...
7. In a single-slit diffraction experiment, a beam of monochromatic light passes through a slit of width 11.0 um. If the fourth dark fringe of the resulting diffraction pattern is at an angle of 6.31°, what is the wavelength of the light? a) 302 nm b) 413 nm c) 602 nm d) 720 nm e) 827 nm
An intense monochromatic light incident on a diffraction grating with slit spacing d is causing an increase of the grating temperature. How should the frequency of the light be changed so that the position of bright fringes does not change.
An intense monochromatic light incident on a diffraction grating with slit spacing d is causing an increase of the grating temperature. How should the frequency of the light be changed so that the position of bright fringes does not change. (Consider that the thermal expansion of the diffraction grating does not damage the slits.) Select one: a. f should be increased. b. f has no effect on the position of the bright fringes. c. f should be decreased. d. f...
Monochromatic light of wavelength 500 nm is incident on a narrow slit. On a screen 2.01 m away, the distance between the second diffraction minimum and the central maximum is 1.85 cm. (a) Calculate the angle of diffraction ? of the second minimum. (b) Find the width of the slit.
Monochromatic light of wavelength 439 nm is incident on a narrow slit. On a screen 2.31 m away, the distance between the second diffraction minimum and the central maximum is 2.18 cm. (a) Calculate the angle of diffraction θ of the second minimum. (b) Find the width of the slit.
Suppose a single slit diffracts monochromatic light at 562 cm and produces the first bright fringe 7.5 cm away from the central axis. The screen is 2.46 m away from the slit. a. How far away from the central axis will the second bright fringe be if monochromatic light of wavelength 495 nm is put through the slit? b. What is the maximum number of dark fringes each of these wavelengths can produce for this slit?
Physics - Single Slit Differaction Light from a distant point source is incident on a narrow slit. Each of the graphs below shows the intensity on a distant screen as a function of theta. The only difference among the six physical situations is the width of the slit. The horizontal scale is the same for all graphs. The vertical scale has been normalized so that the maximum intensity is the same for all cases. Rank the cases according to the...