Question

one question part a b c d
Determine the pressure (bar) of saturated liquid water at T = 1 17.5°C using the table below Note: Give your answer to three decimal places Note: Your answer may be slightly different from the given answer (within 5%) due to the method by which the answer is calculated Properties of Saturated Water: Temperature Table Temp Pres Specific Volume Sp. Internal Energy Specific Enthalpy Specific Entropy kJ/kg hf kJ/k kJ/kg-K Temp sf bar vfx 10v 0 0 uf hf 50 0.12350 1.0121 12.031 209.47 2443.0209.48 2382.1 2591.6 0.7039 8.075550 60 0.199411.0170 7.670 251.61 2456.2 251.63 2357.52609.1 0.8323 7.908760 70 0.31189 1.02275.042 293.65 2469.1 293.69 2332.72626.3 0.9567 7.754570 0 0.47391 1.0289 3.407 335.60 2481.7 335.65 2307.5 2643.2 1.0772 7.6114 80 90 0.70141 1.0359 2.360 377.492494.1 377.56 2282.1 2659.6 1.1941 7.4782 90 100 1.0135 1.0434 1.673419.39 2506.0 419.50 2256.1 2675.6 1.3080 7.3540 100 120 1.9854 1.0604 0.892 503.47 2528.8 503.682202.2 2705.8 1.52757.1288 120 140 3.6130 1.08000.509 588.342549.6 588.732144.7 2733.4 1.73806.9291 140 160 6.1785 1.1022 0.307 674.392567.9 675.07 2082.6 2757.6 1.94146.7494160 180 10.022 1.1275 0.194 761.802583.2 762.93 2014.8 2777.7 2.1387 6.5849 180 200 15.539 1.1564 0.127 850.66 2594.8 852.46 1940.3 2792.7 2.3307 6.4314 200 220 23.179 1.1897 0.086 941.12 2601.9 943.881857.8 2801.7 2.5181 6.2852 220 240 33.4431.2287 0.060LO33.582603.5 1037.691765.6 2803.3 2.70216.1429 240 260 46.887 1.2753 0.042 L128.80 2598.5 1134.781661.6 2796.4 2.8844 6.0010 260 2801 64.118 1.3323| 0.0301し227.96| 2585.5| 1236.50| 1542.4| 2778.9| 3.0676| 5.8561| 280

Answer 1

G- a fui 1175 120 1. 9154 1.013 s + ( 17.5-10-) 3

ㄒㄧ二 180°C lso @ 180c = 362-33 Kyk fg @ 180.c.= 2014-1 k3/K Finn Equation (D) we get = 1685.7084 k

3ookP 30 30688 320 31 03. 3068.8 +/aio-3-3601x(olog.c-Zv6K @ 310.3. = 3 20 3 [email protected].二3089. 81.2 kHy Fromm gwen table r-1. 013S41 20-oo 12o 드 1, 8 6 3 gl2S p = 1.864 bar