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U n velow, or select another question 04(0/1) te: 1/4 Given the following sampling distribution of one mean with a sample siz
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Answer #1

Using normal curve,

\sigma\bar{x} = (87 - 1) = 1  

Now,

\sigma\bar{x} = \sigma / sqrt(n)

\sigma = \sigma \bar{x} * sqrt [ n]  

= 1 * 8

= 8

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