Question

Hi can you work out problem number 7 for me and show me step by step how you did this question.

Question 7 of refraction of a medium if the angle of incidence in air is 40 degrees and the What is the index angle of refraction is 29 degrees? Question 8 What is the angle of incidence for a light ray traveling from water into flint glass (ne1.7 angle of refraction is 30 degrees? What is the angle of reflection? 0), if the Question 9 The refractive index of blood increases as the blood's glucose concentration increases. (For normal glucose content it ranges from 1.34 to 1.36; it is higher than 1.33 for water because of all the additional organic compounds in the blood). Therefore, measuring the index of refraction of blood can help determine its glucose concentration. In a hypothetical process,a hemispherical container holds as small sample of blood, as seen below. A narrow laser beam enters perpendicular to the bottom curved surface and into the sample. The light reaches the blood-air interface at an angle of 40.0 degrees relative to the normal line. The light leaves the blood and passes through the air to a row of tiny detectors at the top indicating that the light beam left the blood at a 61.7-degree angle. Determine the refractive index of the blood. Light detectors 2r 1.00 Air Blood Laser beam

Answer 1

Angle of incidence i = 40 degree angle o refraction r = 29 degree From snell's law, refractive index n = sin i /sin r = sin 40/sin 29 = 1.325855 = 1.3226 a^n g = 1.70 refractive index of glass w r t air angle of refraction r = 30 degree refractive index of water with respect to a n a^n w = 1.33 (internet) therefore Refractive index of glass with respect to water w^n g = a^n g/a^n w = 1.70/1.33 From snell's law, w^n g = sin i /sin r i = sin^- 1 (w^n g times sin r) = sin^- 1 (1.70/1.33 times sin 30) i = 39.725 degree