z-(x, y)over the region R. 9. Find the area of the surface given by.y)over the region...
Find the area of the surface given by z = f(x, y) over the region R. (Hint: Some of the integrals are simpler in polar coordinates.) f(x, y) = x2 + y2, R = {(x, y): 0 = f(x,y) 3}
8. Find the area of the surface given by z - f(x, y) over the region R. f(x,y)- 42-x2-y2, R = {(x,y): x2 +y2 29 8. Find the area of the surface given by z - f(x, y) over the region R. f(x,y)- 42-x2-y2, R = {(x,y): x2 +y2 29
Use a change of variables to find the volume of the solid region lying below the surface -f(x, y) and above the plane region R x, y)xy)e- R: region bounded by the square with vertices (4, 0), (6, 2), (4, 4), (2, 2) Use a change of variables to find the volume of the solid region lying below the surface -f(x, y) and above the plane region R x, y)xy)e- R: region bounded by the square with vertices (4, 0),...
Find the average value of f(x, y) over the region Rwhere A is the area of R in the following equation. Average value - Ā J 1(x,y) dA f(x,y) = xy R: rectangle with vertices (0, 0), (7,0), (1, 2), (0, 2) Enter a number Submit Answer Practice Another Version
Find the volume of the solid bounded above by the surface z = f(x,y) and below by the plane region R. f(x, y) = x2 + y2; R is the rectangle with vertices (0, 0), (9, 0), (9, 6), (0, 6) ( ) cu units
6. Find the center of mass of the rectangular lamina with vertices (0,0), (6,0), (0, 24) and (6, 24) for the density p = kxy. 7. Find the area of the surface given by z =f(x,y) over the region R. f(x,y) = 3 – 2x + 5y R: square with vertices (0,0), (4,0),(4,4),(0,4)
Evaluate the surface integral f(x,y,z) dS using a parametric description of the surface. f(xyz) = 4x, where S is the cylinder X + z2-25, 0 ys2 The value of the surface integral is (Type exact answers, using T as needed.) Find the area of the following surface using the given explicit description of the surface. The cone z2 = (x2 +y2) , for Oszs8 Set up the surface integral for the given function over the given surface S as a...
Evaluate the surface integral lis(r,y,z) (x, y, z) ds where f(x, y, z) = x + y + z and o is the is the surface of the cube defined by the inequalities 0 < x < 5,0 Sy < 5 and 0 <3 < 5. [Hint: integrate over each face separately.] 1 f(x, y, z) ds =
Find the area of the lateral surface over the curve C in 6. the xy-plane and under the surface z - f(x,y) f(x,y)-h, C:y-1 -x2 from (1,0) to (0,1) Surface: Lateral surface area - f(x, y) ds z =f(x, y) Lateral surface xy) As C: Curve in xy-plane Find the area of the lateral surface over the curve C in 6. the xy-plane and under the surface z - f(x,y) f(x,y)-h, C:y-1 -x2 from (1,0) to (0,1) Surface: Lateral surface...
11. Find the area of the portion of the surface f(x, y) 1-x2+ y that lies above the triangular region with vertices (1, 0, 0), (0, -1, 0) and (0, 1, 0). 11. Find the area of the portion of the surface f(x, y) 1-x2+ y that lies above the triangular region with vertices (1, 0, 0), (0, -1, 0) and (0, 1, 0).