Question

Enter electrons as e The following skeletal oxidation-reduction reaction occurs under basic conditions. Write the balanced OXIDATION half reaction. 12 +3,032- S032- ited Reactants Products

Answer 1

H-Ho + → 592 * I" In 200 m l 0 -> OH 2x=0 X+ 3(-22=-21 1420 2x+ 3(-22=-2 28 - 74 2413 x=0 x=44 x=+2 oxidation half reaction Reduction half reaction 382 - so-2 Ij ->I' balance all aloms except oxygen and hydrogen qo2 » 250g 2 1 I 221 balance oxygen atoms by adding ot' ions then balance hydrogen atoms by adding Ho molecules. Repeat this process up to balanceing of all atoms +60'>250 +340 I = 21"}

balance charge by adding electrons to +600°=> 20717349 thé" It nē => 21"' integer to equalise multiply with suitable number of electrons X2 Om 20 + 607 2 250 +34,0 +421 | 21+48%-> 4I add both 10+ 601" ~ 280 2+ 34,07 400 21 + ax -> 41'' 2 I +60173250+ 49'+ 3H0v

Balanced oxidation - half reaction 20² + 60th - 2592 + 3H0+4E ~ Balanced Reduction half reaction I + 2€! -> 21''