Parts a through d are a part of the SAME problem.
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Parts a through d are a part of the SAME problem.
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An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length o...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
1.) An object is placed in front of a diverging lens with a focal length of...
1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____ cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use...
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use ray tracing to get the image and measure image distance. Describe the image from your drawing (upright/inverted, real/virtual, bigger/smaller). Please use ruler to get as accurate as you could (b) Use the lens equations to calculate the location of the image and its magnification. Describe the image from your calculation (upright/inverted, real/virtual, bigger/smaller).
An object 2.00 cm high is placed 45.3 cm to the left of a converging lens...
An object 2.00 cm high is placed 45.3 cm to the left of a converging lens having a focal length of 40.3 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position cm magnification...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of...
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
gibly drawn to scale ray diagrams showing h ation ng configuration: converging lens of 15em fixed focal length em in length. An object is placed at 0.0 em, can be detected is placed somewhere...
gibly drawn to scale ray diagrams showing h ation ng configuration: converging lens of 15em fixed focal length em in length. An object is placed at 0.0 em, can be detected is placed somewhere on an optical bench of 240 and a screen is placed where ever a focused image Use the illustrations on the following pages to construct one ray diagram for each of the following situations, using the basic configuration given above. Situation a) Measuring from the object...
9. -15 points KatzPSE1 38.P.076 My Notes Ask Your The figure below shows an object placed a distance doi from one of two converging lenses separated by s 1.00 m. The first lens has focal length fi 23...
9. -15 points KatzPSE1 38.P.076 My Notes Ask Your The figure below shows an object placed a distance doi from one of two converging lenses separated by s 1.00 m. The first lens has focal length fi 23.0 cm, and the second lens has focal length 2 47.0 cm. An image is formed by light passing through both lenses at a distance = 12.0 cm to the left of the second lens. Include the sign of the value in your...
1. (5 marks) The image shows a glass rod that is partially inside a liquid. The...
1. (5 marks) The image shows a glass rod that is partially inside a liquid. The part of the rod that is inside the liquid is invisible. Why? Explain clearly 2. (5 marks) Suppose an object is placed 6 cm in front of a converging lens (convex lens) with a focal length of 10 cm. Determine: a) the distance between the image and the object. b) the magnification and the image properties (real/virtual, inverted/upright, larger/smaller).
This is a two part question. Part 1. To look closely at a small object, such...
This is a two part question. Part 1. To look closely at a small object, such as an insect or a crystal, you bring it close to your eye, making the subtended angle and the retinal image as large as possible. But your eye cannot focus sharply on objects that are closer than the near point, so the angular size of an object is greatest when it is placed at the near point (25 cm away from a “normal” eye)....
Question 3 (2 points) This assignment is set up for sequential assessment. Complete each question and...
Question 3 (2 points) This assignment is set up for sequential assessment. Complete each question and submit the answer before moving on to the next question. Correct answers for each question will be made available once the maximum number of attempts have been made for each submission. Refraction - CONVERGING and DIVERGING Lenses In these problems, you will solve for the object distance do, or focal length f, or the type of lens. Pay attention to the SIGN Convention. The...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
(a) An object is placed 7.5cm from a converging lens having a 5cm focal length. Use ray tracing to get the image and measure image distance. Describe the image from your drawing (upright/inverted, real/virtual, bigger/smaller). Please use ruler to get as accurate as you could (b) Use the lens equations to calculate the location of the image and its magnification. Describe the image from your calculation (upright/inverted, real/virtual, bigger/smaller).
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
gibly drawn to scale ray diagrams showing h ation ng configuration: converging lens of 15em fixed focal length em in length. An object is placed at 0.0 em, can be detected is placed somewhere on an optical bench of 240 and a screen is placed where ever a focused image Use the illustrations on the following pages to construct one ray diagram for each of the following situations, using the basic configuration given above. Situation a) Measuring from the object...
9. -15 points KatzPSE1 38.P.076 My Notes Ask Your The figure below shows an object placed a distance doi from one of two converging lenses separated by s 1.00 m. The first lens has focal length fi 23.0 cm, and the second lens has focal length 2 47.0 cm. An image is formed by light passing through both lenses at a distance = 12.0 cm to the left of the second lens. Include the sign of the value in your...
1. (5 marks) The image shows a glass rod that is partially inside a liquid. The part of the rod that is inside the liquid is invisible. Why? Explain clearly 2. (5 marks) Suppose an object is placed 6 cm in front of a converging lens (convex lens) with a focal length of 10 cm. Determine: a) the distance between the image and the object. b) the magnification and the image properties (real/virtual, inverted/upright, larger/smaller).
Question 3 (2 points) This assignment is set up for sequential assessment. Complete each question and submit the answer before moving on to the next question. Correct answers for each question will be made available once the maximum number of attempts have been made for each submission. Refraction - CONVERGING and DIVERGING Lenses In these problems, you will solve for the object distance do, or focal length f, or the type of lens. Pay attention to the SIGN Convention. The...
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