Question

[C Language] -- NO HARD CODING --Everything should be expandable if more or different cities get added

Create a report that lists all of the cities that patients live in and provide a count for each city of how many patients come from that city. Print this list out in alphabetical order based on city name.

[needed array] char city[][15] = {"Lakeland","Orlando","Tampa","Lakeland","Tampa","Lakeland","Orlando","Orlando","Lakeland","Lakeland","Orlando","Tampa","Tampa","Lakeland","Orlando");

The output should be something like this

Lakeland 6

Orlando 5

Tampa 4

Answer 1

C code:

#include <string.h>
#include <stdio.h>
int main()
{
char city[][15] = {"Lakeland","Orlando","Tampa","Lakeland","Tampa","Lakeland",
"Orlando","Orlando","Lakeland","Lakeland","Orlando","Tampa","Tampa","Lakeland","Orlando"};
char temp[50];
  
int len = sizeof(city)/sizeof(city[0]);
for(int i=0;i<len;i++)
{
for(int j=i+1;j<len;j++)
{
if(strcmp(city[i],city[j])>0)
{
strcpy(temp , city[i]);
strcpy(city[i],city[j]);
strcpy(city[j],temp);
}
}
}
int count=1;
strcpy(temp,city[0]);
for(int i=1;i<=len;i++)
{
if(strcmp(temp,city[i])==0)
count++;
else
{
printf("%s %d\n",temp,count);
count = 1;
strcpy(temp , city[i]);
}
}
  
return 0;
}
Execution screenshots:

main.c 1 #include <string.h> 2 #include <stdio.h> 3 int main) 4 char city[][15] = {"Lakeland","Orlando","Tampa","Lakeland","Tampa","Lakeland", 5- "orlando","Lakeland","Lakeland","Orlando","Tampa","Tampa","Lakeland", "Orlando"} ; "Orlando", 6 7 char temp[50]; int len sizeof(city) /sizeof(city [0] ); for(int i-0;i<len;it+) { for(int j-i+1; j<len; j++) 10 11 . 12 13 if (strcmp (city[i],city[j])>0) { strcpy(temp, city[i]); strcpy(city[i],city[j]); strcpy(city[j],temp); 14 15- 16 17 18 19 } 20 21 int count 1; strcpy(temp,city[0]); for (int i-1;i<=len;i++) 22 23 24 25 if (strcmp(temp,city[i])==0) count++ else 26 27 28 { printf("%s %d\n",temp,count); Count 1; strcpy(temp , city[i]); } 35 return 0; 36 37 38

input Lakeland 6 Orlando 5 Tampa 4 ...Program finis hed with exit code 0 Press ENTER to exit console .

Note: Please like the answer.Thank you.