x̅ =12.25, σ =0.20, n =75
95% Confidence interval :
At α = 0.05, two tailed critical value, z crit = NORM.S.INV(0.05/ 2) = 1.960
Lower Bound = x̅ - z-crit*σ/√n = 12.20
Upper Bound = x̅ + z-crit*σ/√n = 12.30
Option 2nd.
3 Scenario 1 A quality control engineer is interested in the mean length of sheet insulation...
A quality control engineer is interested in the mean length of sheet insulation being cut automatically by machine. The desired mean length of the insulation is 12 feet. It is known that the standard deviation in the cutting length is 0.15 feet. A sample of 70 cut sheets yields a mean length of 12.14 feet. This sample will be used to obtain a 99% confidence interval for the mean length cut by machine. Determine whether the statement is true or...
A quality control engineer is interested in the mean length of sheet insulation being cut automatically by machine. The desired length of the insulation is 12 metres. It is known that the standard deviation in the cutting length is 0.15 metres. A sample of 144 cut sheets yield a mean length of 12.14 metres. This sample will be used to obtain a 90% confidence interval for the mean length cut by machine. What are the two limits of the confidence...