Question

a research institute poll asked respondents if they felt vulnerable to identify theft. in the poll, n=964 and x=580 who said yes use a 99% confidence level

X 7.2.17-T Question Help In a study of speed dating male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1 = not attractive, 10 extremely attractive) Construct a confidence interval using a 99% confidence level. What do the results tell about the mean attractiveness ratings of the population of all adult females? 7.9.2, 10.7,4,6,7,8,9,6,9 - What is the confidence interval for the population mean? << (Round to one decimal place as needed) Enter your answer in the edit fields and then click Check Answer 1 part st remaining Clear All Check Answer LE FESTER W TESTET Permissions Contact Us 42 AM A 130/2020 eText O Type here to search 00 e 9 "

Answer 1

* A research institute poll they felt vulnerable asked respondents to identify thert. if - in the poll. n=964 4 x=580 who said yes use a 99% confidence internal > 99% confidence interval for population proportion 1 + (2 + (x + (+ (1-2) is to say =10.6016 | 4 2112 = 112.88 - (from table) p = 580 0.60 LC - 964 2.58

Paco.com 0.6016 † 12.58 * 16.6016 * 0.3934))). (2.58 16 * 964 = (0.6016 t (2.98 +0.0157)] = [0.6016 $ 0.0406) = [0.561, 0.6422) confident the population proportion we can say 99% (P) is lies within [0.561 to [0.6422]

*) In a study of speed dating construct a confidence interval using a 94% confidence level what do the result tell about the mean attractiveness rating of the population of all adult females ? * tet xi rate the attractiveness of their female dates. n= 12 =(7,9, 2, 10, 7,4,6, 7, 8, 9,6,9) Harăt (tale,df *

where M= Population mean for attractiveness rating of all adult Females. ão sample mean = Eli = [ 7+9+2+10 + 7 +4 +6 + 7+8 +966 +97 12 = 4 - 7 so sample standard deviation = Eldi - 12

lib 6=x x 12.2962. = 12.2962 s= 15-2727 i tz 52-5]- [85] + ™ - [h to thtitetit b tot bt soth to K 7 = (216-b) + zlt - g) + 21t-b.) +z15-8) + zlt-t) + 255-9) + z E-h) telt-++zlt-al] tz/t-2)test-b] +z1t -D) ) * T = = 71*-:23 m in

- td12, df = tool,!= 3.1058 (from table) M=[7 13.1058 + =[7 2.0586] (2.2962 / 512 ) = [4.9414, 9.0586] we can say 99% confident that 1 mean population l is lies within 15 to [90]. 5 < M L 9.0