Question

4. Extra Credit EC 3-37: Aluminum chloride, Al,Cl,is an inexpensive reagent made by treating scrap aluminum with chlorine according to theced A 12 Unbalanced: 2Al CAl,cl used in many industrial processes. It is AI: 2 unbalanced equation. A a. Balance the chemical reaction:2A4502()re mixed? b. Which reagent is the limiting reagent if 2.70 g Al and 3C2 LS) c. What mass of Al,Cls can be produced? (Theoretical Yield) d. What mass of excess reactant will remain when the reaction is complete?

Answer 1

A) 2 Al (s) + 3 Cl_2 (g) rightarrow Al_2 Cl_6 (s) b) 1 mol of Al = 27 g of Al therefore 2.7 g of Al = 2.7/27 mole of Al = 0.1 mole of Al 1 mole of Cl_2 = 71 g of cl_2 therefore 4.05 g of Cl_2 = 0.057 mole of Cl_2 For reaction there is 2 mol of Al and 3 mol of Cl_2 is needed for reaction, 2 Al = 0.05 mol 3 Cl_2 = 0.019 mol therefore Limiting reagent is Cl_2 c) 0.01 g mol of Al_2 Cl_6 could form almostequalto 1 mol Al_2 CL_6 = 98 g almostequalto 0.019 g mol of Al_2 Cl_2 = 1.862 g of Al_2 Cl_6 is produced (Actual yield) Theortical yield = 98 g d) mole of excess reactant left = 0.05 - 0.019 mol of 2 Al almostequalto 0.062 mol of Al is left after the reaction