Question

An RL circuit with a 6-12 resistor and a 0.03-H inductor carries a current of 1 A at t=0, at which time a voltage source E(t) = 6 cos (150t) Vis added. Determine the subsequent inductor current and voltage. I(t) = 0

Answer 1

of thei=ocos (TOP) at Lahtris Ect) el + i = ELL) oo 0.03. + 2001 = 6cos (1901) - 200 cos (1501) Mitl=es200 dito e 2007 2004 by te 20072001 - 20000s (1901)e mat sle 20 jj 722062007) dt = | 200 ces (rot) e 2.0 2t ie 2oot fc = /200 califotle root dt. i = 2002-2017 560s(150t/ezcotutte) - 2 200

1+2000 e 2007 -qoo1 12 2007/200 cos (150t) 150 sin Cioot)) 2 200²1502 i 200 Cos (1567) +15 ocsin (150t), on 312.5 using our intial value of i(0)=1; (1) - 200 cos (150t) +1501in (150+)+ ke-2007 312.5 1- ilo] = 2.00 +keº - 20 stk KE = 312.57.00 = ... ilt) = 200 COJ (1507) + 150 sia (150+) 7112.5e-2007 200 312-5 206 212- CH 312.5 - 200 cos urot) + 150 sin (150t) +112-jé 20 1218-2001 312-5

To find the voltage drop Lot - 0.03630000" (1507) + 22500 507) 225002 Joot) 312.5