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please answer number 6 and show work thank you
by what traction of its kinetic energy is rotational? Problem 6: Stoplight A 21 kg stoplight hangs at the end of a 6.0-m-long
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Answer #1

a] Let tension be T,

since it is at equilibrium, net torque = 0

T* 3 - mg*L/2 cos 37 degree - Mg L cos 37 degree = 0

T*3 - 12*9.8*6/2*0.8 - 21*9.8*6*0.8 = 0

T = 423.4 N

b] Vertical force at A = Mg+mg = 21*9.8+12*9.8 = 323.4 N

Horizontal force = T = 423.4N

  

  

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