Help me please
Substance |
S° (J/mol×K) |
Al (s) |
28.33 |
Al2O3 (s) |
50.92 |
Cl2 (g) |
223.07 |
H2 (g) |
130.68 |
N2 (g) |
191.61 |
O2 (g) |
205.14 |
Si (s) |
18.83 |
SiCl4 (g) |
330.73 |
SiHCl3 (g) |
330.73 |
SiH2Cl2 (g) |
285.71 |
SiH3Cl (g) |
313.87 |
SiH4 (g) |
204.62 |
Si3N4 (s) |
101.3 |
SiO2 (s) |
41.84 |
1. Predict the sign of
S°rxn for the following processes. Then calculate
S°rxn using the standard values just given.
sign of |
|
|
a. SiO2 (s) |
||
b. Al2O3 (s) |
||
c. Si (s) + 2 Cl2 (g) |
||
d.3 Si (s) + 2 N2 (g) |
Thank you!
sign of |
|
|
a. SiO2 (s) |
+ ve (positive) |
|
b. Al2O3 (s) |
+ ve (positive) |
|
c. Si (s) + 2 Cl2 (g) |
- ve (negative) |
|
d.3 Si (s) + 2 N2 (g) |
- ve (negative) |
Explanation :
a) SiO2 (s) Si (s) + O2
(g)
S°rxn = ( 18.83 +
205.14 ) - 41.84
S°rxn
= 182.13 J/mol K
b) b. Al2O3 (s) 2 Al (s) +
3/2 O2 (g)
S°rxn = (2 x
28.33 + 3/2 x 205.14) - 50.92
= 313.45 J/mol . K
c)
S°rxn = 330.73 -
(18.83 + 2 x 223.07)
= - 134.24 J/mol K
d)
S° rxn = 101.3 -
18.83 +2 x 191.61
= - 300.75 J/mol K
Help me please Substance S° (J/mol×K) Al (s) 28.33 Al2O3 (s) 50.92 Cl2 (g) 223.07 H2...
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