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B. *A gas occupies 0.67 L at 350 K. what temperature is required to reduce the volume by 45%?
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(3) Initia. N Volume ) Vi= 0.67 Final volume, is obtained by Teddery 45% 4V Let, Final tempezcture beTe- VT 350 x6.55Therefore the required temperature is 192.5 k

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