If a driver provides 3.07 g of ethanol (C2H6O) into the Breathalyzer, what is the concentration...
If a driver provides 3.07 g of ethanol (C2H6O) into the Breathalyzer, what is the concentration of acetic acid (C2H4O2) if we assume the final volume is 100. mL?
Homework Answers
Moles of ethanol = mass / molar mass
= 3.07 / 46
= 0.0667 moles
In breathalyzer equation
3C2H5OH + 2K2Cr2O7 + 8H2SO4 = 2Cr2(SO4)3 + 3CH3COOH + 2K2SO4 + 11 H2O
so mole of C2H5OH = mole of CH3COOH = 0.0667
So Molarity = mole / volume ( in litre)
= 0.0667 / 0.1
= 0.667 M
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