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Need help with these linear algebra problems.

Let TARS - R* be the linear transformation with standard matrix A A= 11 2 1 4 2 4 2 8 2 1 | 2 3 3 12 3 6 5 9 1. Find a basis

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Answer #1

son TA : RP → RŲ A = [1 2 1 4 37 II e II 1 2 3 3 129] By Reducing A to echelon form Using Row transformations By R2-2R1, R3-Rby Radf.3. fa-3R., then pan. Ry - 282 NII 0 3 0 51171 lo 1 -1 0 -1717 Lo 0 0 17 Loo ooo since pivot colums are 1, 2 & 4. 1) B

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