Question

8 ΚΩ - 8, 8 kg Το ξ6 ΚΩ Problem 8) Find all of the node voltages in the circuit and the current lo, and 5001x<+ also report the power in the dependent Source. 3 kΩ m o c ή 1 ΚΩΥ ξι ΚΩ (Ε) 24V 10 kΩ !

Answer 1

skr MM M 5001 +24v Apply Nodal analysis 4 = 24 V super node Va-va = 500 Ix but I g = who ya » Vsx103 Va-va = 500*76 x 103 Va-vd = 0.5lb Va -0.546-vd = 0 0 vo (***) * V6 (6+) za 0:29166 Y-0.546 + 0.4333 Vd = 3->

Vb-vcubova vb-vd, ub-o . vant vo(1+++) - Y = 24 -0.1666 Va +2.5 V6-0-333 Vd = 24 ->3 solve eqo, @@ - Va=16v; V6=12v ; vd = 10 v Node voltages Va=16v; V6 = 12v Vc = 24v; vd = lo v Apply kcl at node a Jo = to the and Jo = the + 0542 = (im)-(0-666m) Jo =(-0.666) m = 0.333 ma Jo= 0.333 mA In = ve a = 12 = 12. mA dependent = (500 5x) (Jo)= (500X12 m)(0.333m) Source 28 153 W = 2 m Wasserted) Power in Solsce