Question

QUESTION 7 A musical instrument shop sells 4 different types of wooden flute. The flutes are intended to be played by beginners, intermediaries, semi- professionals or professionals. The shop currently has 40% beginner flutes, 30% intermediary flutes, 20% semi-professional flutes and 10% professional flutes, with the prices being $100 for a beginner flute, $200 for a intermediary flute, $500 for a semi-professional flute, and $4000 for a professional flute. What is the weighted average price of wooden flutes currently for sale in the shop (to the nearest dollar)? Note: Enter the answer as an integer. QUESTION 8 The data below are from a random sample of 8 professional wooden flute players. Each player was asked to play and hold a single note for as long as possible. The number of seconds each note was held is shown below. 32 28 33 27 35 25 31 35 The difference between 3rd and 2nd quartiles (Q3- 2) would be (one decimal place).

Answer 1

Question 7: The shop currently has 40 % beginner flutes, 30 % intermediary flutes, 20 % semi- professional flutes, and 10 % professional flutes. The prices are $100 for beginner flute, $200 for intermediary flutes, $500 for semi-professional flutes, and $4000 for a professional flutes The weighted average price of wooden flutes currently for sale in the top is calculated as follows: ( 40 200 +- $500 + - X $40 Weighted Average = (40% Ⓡ$100)+(30% × $200)+(20% Ⓡ$500)+(10% Ⓡ$4000) 30 20 (10 x $100 + — 100 ( 100 = $40+ $60+ $100+ $400 = $600 100 100 Thus, the weighted average price of wooden flutes is $600).

Question 8: The data below is from a random sample of 8 professional wooden flute players: 32, 28, 33, 27, 35, 25, 31, 35 Arrange the data as follows: 25, 27, 28, 31, 32, 33, 35, 35 As the number of observations is 8, that is, even in numbers. Thus, the median is given as follows: term + -+1 term Median = Metion () term + (0 +1) term 2 2 4th term + 5th term 2 31+32 2 = 31.5 Median is also known as 2nd quartiles, thus Q2 = 31.5.

The third quartile is derived as follows: Third quartile=Qz _3(n+1) 4 3(8+1) = 6.75th term Thus, 6.75 is not an integer, so the interpolation is to be done to find the value. This means the value lies between 6 and 7 terms, which are 33 and 35. Q; = 33+0.75(35 – 33) = 33+1.5 = 34.50 Thus, Q = 27.25 22 = 31.5 93 = 34.50 The difference between the 3rd and 2nd quartile (9; -22) would be (34.50 – 31.5)= 3).