Question

CAN ANYONE PLEASE HELP ME SOLVE THIS PROBLEM WITHOUT RETURNING ERRORS, BAD TOKENS, ETC.

PLEASE INCLUDE CORRECT SYNTAX...MUST BE IN PYTHON 3 AND PASS THE TEST

Write a function analyze_text that receives a string as input. Your function should count the number of alphabetic characters (a through z, or A through Z) in the text and also keep track of how many are the letter 'e' (upper or lowercase). Your function should return an analysis of the text in the form of a string phrased exactly like this: “The text contains 240 alphabetic characters, of which 105 (43.75%) are ‘e’.”

USING FUNCTION: def analyze_text(text):

Thank You For Your Help!

Answer 1

Python3 Code:

def analyze_text(text):

alphabets = 0 #initializing the count of alphabets as 0

count_e = 0 #initializing the count of 'e's as 0

for i in text: #for every character in text

if(i>='a'and i<='z'): #if character is lowercase alphabet

alphabets+=1 #increasing the count of aplhabets by 1

elif(i>='A'and i<='Z'):#if character is uppercase alphabet

alphabets+=1 #increasing the count of aplhabets by 1

if(i=='e'or i=='E'): #if character is 'E'

count_e+=1 #incrementing the count of 'e's by 1

percentage_of_e = (count_e*1.0/alphabets*1.0)*100.0 #calculating the percentage of es

percentage_of_e = round(percentage_of_e,2) #rounding to 2 decimal places

return "The text contains "+str(alphabets)+" alphabetic characters, of which "+str(count_e)+"("+str(percentage_of_e)+"%) are 'e'."

Screenshot of the code with indentation and it's output in python3 shell: