Homework Answers
confidence interval for
variance is (14.9, 34)
Confidence interval for standard deviation is (3.9, 5.8)
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The lifetimes of inexpensive wristwatches of a sample of 21 watches has a standard deviation of...
10. Stock Prices A random sample of stock prices per share (in dollars) is shown. Find...
10. Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the 90% confidence interval for the variance and standard deviation for the prices. Assume the variable is normally distributed. Chapter 7 Confidence Intervals and Sample Size 404 3. Using Table G. find the values for en and icht a a0.05, n 12 b a 0.10,n-20 a0.05, n27 12.00 28.37 47.50 13.88 7.50 53.81 28.25 10.87 26.69 43.00 75.37 3.81 45.12 13.62 d a0.01,n=6 60.50...
Lifetimes of AAA batteries are approximately normally distributed. A manufacturer wants to estimate the standard deviation...
Lifetimes of AAA batteries are approximately normally distributed. A manufacturer wants to estimate the standard deviation of the lifetime of the AAA batteries it produces. A random sample of 17 AAA batteries produced by this manufacturer lasted a mean of 11 hours with a standard deviation of 2.5 hours. Find a 95% confidence interval for the population standard deviation of the lifetimes of AAA batteries produced by the manufacturer. Then complete the table below.Carry your intermediate computations to at least...
A simple random sample of size 14 has mean 3.67 and standard deviation 1.75. The population...
A simple random sample of size 14 has mean 3.67 and standard deviation 1.75. The population is approximately normally distributed. Construct a 99% confidence interval for the population mean. 1. The parapmeter is the population (choose one) mean, standard deviation, variable, proportion 2. The correct method to find the confidence interval is the (choose one) z, t, chi square method
A random sample of 49 observations is used to estimate the population variance. The sample mean a...
A random sample of 49 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 59 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 90% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval b. Construct the...
A random sample of 43 observations is used to estimate the population variance. The sample mean...
A random sample of 43 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 68.5 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 95% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval to b. Construct...
Find the 90% confidence interval for the variance and the standard deviation of the ages of seniors at Oak Park College if a sample of 24 students has a standard deviation of 2,3 years
Find the 90% confidence interval for the variance and the standard deviation of the ages of seniors at Oak Park College if a sample of 24 students has a standard deviation of 2,3 years. Assume the variable is normally distribution
Cell Phone Lifetimes A recent study of the lifetimes of cell phones found the average is...
Cell Phone Lifetimes A recent study of the lifetimes of cell phones found the average is 24.3 months. The standard deviation is 2.6 months. If a company provides its 32 employees with a cell phone, find the probability that the mean lifetime of these phones will be less than 23.7 months. Assume cell phone life is a normally distributed variable, the sample is taken from a large population and the correction factor can be ignored. Round the final answer to...
Find the critical values x?and XR for the given confidence level c and sample size n....
Find the critical values x?and XR for the given confidence level c and sample size n. C=0.8, n=30 xL= (Round to three decimal places as needed.) Find the critical values x and x for the given confidence level c and sample size n. c=0.9, n=21 x?L= (Round to three decimal places as needed.) Use technology to construct the confidence intervals for the population variance o2 and the population standard deviation o. Assume the sample is taken from a normally distributed...
A simple random sample of size 39 has mean 3.64. The population standard deviation is 1.55....
A simple random sample of size 39 has mean 3.64. The population standard deviation is 1.55. Construct a 95% confidence interval for the population mean. 1.The parameter is the population (choose one) mean, proportion, standard deviation, variance 2. The correct method to find the confidence interval is (choose one) z, t, chi square method
2 3 5 Lifetimes of AAA batteries are approximately normally distributed. A manufacturer wants to estimate...
2 3 5 Lifetimes of AAA batteries are approximately normally distributed. A manufacturer wants to estimate the standard deviation of the lifetime of the AAA batteries it produces. A random sample of 15 AAA batteries produced by this manufacturer lasted a mean of 10.5 hours with a standard deviation of 2.4 hours. Find a 90% confidence interval for the population standard deviation of the lifetimes of AAA batteries produced by the manufacturer. Then complete the table below. Carry your intermediate...
10. Stock Prices A random sample of stock prices per share (in dollars) is shown. Find the 90% confidence interval for the variance and standard deviation for the prices. Assume the variable is normally distributed. Chapter 7 Confidence Intervals and Sample Size 404 3. Using Table G. find the values for en and icht a a0.05, n 12 b a 0.10,n-20 a0.05, n27 12.00 28.37 47.50 13.88 7.50 53.81 28.25 10.87 26.69 43.00 75.37 3.81 45.12 13.62 d a0.01,n=6 60.50...
A random sample of 49 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 59 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 90% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval b. Construct the...
A random sample of 43 observations is used to estimate the population variance. The sample mean and sample standard deviation are calculated as 68.5 and 3.1, respectively. Assume that the population is normally distributed. (You may find it useful to reference the appropriate table: chi-square table or F table) a. Construct the 95% interval estimate for the population variance. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval to b. Construct...
Find the critical values x?and XR for the given confidence level c and sample size n. C=0.8, n=30 xL= (Round to three decimal places as needed.) Find the critical values x and x for the given confidence level c and sample size n. c=0.9, n=21 x?L= (Round to three decimal places as needed.) Use technology to construct the confidence intervals for the population variance o2 and the population standard deviation o. Assume the sample is taken from a normally distributed...
2 3 5 Lifetimes of AAA batteries are approximately normally distributed. A manufacturer wants to estimate the standard deviation of the lifetime of the AAA batteries it produces. A random sample of 15 AAA batteries produced by this manufacturer lasted a mean of 10.5 hours with a standard deviation of 2.4 hours. Find a 90% confidence interval for the population standard deviation of the lifetimes of AAA batteries produced by the manufacturer. Then complete the table below. Carry your intermediate...
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