delta H reaction = -1074 - 1360 - 52.4
delta H reaction = 2486.4 kJ
2. Calculate AH for the reaction of ethylene with F2. CHA(g) + 6 F2(g) → 2...
6.65 From the enthalpies of reaction H2(8) + F2(8) 2 HF(8) AH = -537 kJ C(s) + 2 F2(8) CF4(8) AH = -680 kJ 2 C(s) + 2 H2(8) —— C2H4(8) AH = +52.3 kJ calculate AH for the reaction of ethylene with F2: C2H4(8) + 6 F2(8) — 2 CF4(8) + 4 HF(8)
Question 8 of 20 Using the equations H2(g) + F2 (g) → 2 HF (g) AH° = -79.2 kJ/mol C(s) + 2 F2 (g) → CF. (g) AH° = 141.3 kJ/mol 2 C(s) + 2 H2 (9) C2H4 (9) AH = -97.6 kJ/mol Determine the enthalpy for the reaction C2H4 (g) + 6 F2 (g) → 2 CF4 (9) + 4 HF (g). kJ/mol
4. (14 pts) Calculate AHr (kJ/mole) for the reaction CaHlg)+ 6 F2(g) >2 CFg) + 4 HF(g) AH (kJ/mole) ? Using only the following data AH (kJ/mole) H2(g)+ F2(g) C(s) + 2 F2(g) 2 C(s)+ 2 H2(g) 2 HF(g) -537.0 -680,0 CF4(g) C2H4(g) + 52.3
5.65 From the enthalpies of reaction H 2 (g)+r 2 (g) longrightarrow2 HF(s) Delta*H = - 537kJ C(s)+2 F 2 (s) longrightarrow CF 4 (g) Delta*H = - 680kJ 2C(s)+2 H 2 (g) C 2 H 4 (g) Delta*H = + 52.3kJ calculate Delta*H for the reaction of ethylene with F 2 : C 2 H 4 (g)+6 F 2 (g) 2 CF 4 (g)+4 HF(g) 5.65 From the enthalpies of reaction H2(8) + (8) 2 HF(8) AH = -537...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
From the enthalpies of reactio: H2( 9.) From the enthalpies of reaction Hale) + F(b) → C(s) + 2F2(g) → 2C(s) + 2H2(g) → Calculate AH for the reaction of ethylene with F2: CzHa() + 6F2(g) 2HF(8) CF(b) CzH4(g) AH =-537 kJ AH = -680 kJ AH = +52.3 kJ → 2CF4(g) + 4HF(E)
3.(15pts) In each case, find the missing AH. (kJ/mole) (a) If 2 Al(s) + Fe2O3(s) ----> Al2O3(s) + 2 Fe(s) AH,xº = -851.5kJ/mol then 1/8 Al2O3(s) + 1/4 Fe(s) --> 1/4 Al(s) + 1/8 Fe2O3(s) AHX = ? (b) If CaO(8) + 3 C(s) --> CaC2(s) + CO(g) AH,” = 464,8 kJ/mol then 6 CaO(s) + 18 C(s) ---> 6 CaCz(s) +6 CO(g) AHX = ? (c) If N2(g) + 2 O2(g) ---> N204(g) and 2 NO2(g) ----> N2(g) +...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) + 6 F2 (g) → 2 CF4(g) + 4 HF (9) can be written as the sum of: CH4 (9) ► 2 C(s) + 2 Ha(o) AH = -52.3 kJ/mol 2 C(s) + 4 Faq) → 2 CF4g) SH -1380 kJ/mol 2 Haq) + 2 Fala) > 4 HF HE.1074 kJimol CsHe(g) + 6 F2 (g) → 2 CF.(g) + 4 HF (g) AH =...
Calculate the standard enthalpy of formation of gaseous carbon tetrafluoride (CF4) using the following thermochemical information: Calculate the standard enthalpy of formation of gaseous carbon tetrafluoride (CF4) using the following thermochemical information: H2(g)F2(g) 2 HF(g) 2 CF4(g)4 HF(g) C2H4(g) +6 F2(g) C2H4(g)2 C(s) 2 H2(g) AH -537 kJ AH 2486.3 kJ AH -52.3 kJ ΔΗ - kJ
What is the enthalpy of reaction, dH(rxn), for the following reaction? C2H4 (g). +. 6 F2 (g). --->. 2 CF4 (g). +.4 HF (g) dH(f) +52.3 -680 -268.5. kJ/mole dH(rxn) - +2486 kJ dH(rxn) = -2486 kJ o dH(rxn) = -2434 kJ • dH(rxn) = -1000.8 kJ