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Assume that you are given an image showing the intensity I(x, y) = c exp[-a(x-b)2]. How...

Assume that you are given an image showing the intensity I(x, y) = c exp[-a(x-b)2]. How does the image look like? Can you compute the corresponding Hessian matrix at pixel (x,y)? Does it tell us anything about the image

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Answer:

Given that:

Assume that you are given an image showing the intensity I(x, y) = c exp[-a(x-b)2]. How does the image look like an you compute the corresponding Hessian matrix at pixel (x,y)

1(x, y) = cela(r-b)2 or ce-a(r-b)

Hessian matvix of I (x,y )is given by

H(I(2,y)) = (- Iry

= (s)

wherel, =c-2a(1-6)}e-ar-62

Ir = (-2ac)(1-0)-ar-b) – 2a(-be-ar-b)2

= (-2ac)e-a(1-62) 1 – 2012 – 6)

If I = ce-2a(1–b) 1,= (-2ac)e-2a(–b)

  = = +4a²ce-2a(1-6)

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