Question

please answer the following question clearly. steam power plant operates with one reheater and one open FWH and one closed FWH. steam enters the high-pressure turbine at15 MPa and 600^oC and the low-pressure turbine at 1MPa and 500 ^oC. The condenser pressure is 5 kPa. Steam is extracted from the turbine at 0.6 MPa for the closed FWH and at 0.2 MPa for the open FWH. In the closed FWH, the feedwater is heated to the condensation temperature of the extracted steam. The extracted steam leaves the closed FWH as a saturated liquid, which is subsequently throttled to the open FWH.

1-Draw a schematic of the cycle

2-Determine the fraction of steam extracted from the turbine for the open FWH

3-Determine thermal efficiency of the cycle

4-Determine the net power output for a mass flow rate of 20 kg/s through the steam generator

Answer 1

"Given that., (a) ""Schematic diagram"": - (b) Properties of all states: \r\n y^1 = h_11 - h_10/h_2 - h_12 = 670 - 505/2720 - 670 = 0.08 (c) ""Thermal Efficiency of cycle"": - \r\n y^11 = (1 - y^1) h_8 + y^1 h_13 - h_9/h_8 - h_5 = (1 - 0.08) 138 + (0.08 times 670) - 505/138 - 3000 = 0.11 W dot T_1/m dot_1 = (h_1 - h_2) + (1 - y^1) (h_2 - h_3) = 860 + 64.4 = 924.4 KJ/kg W dot T_2/m dot_1 = (1 - y_1) (h_4 - h_5) + (1 - y^1 - y^11) (h_5 - h_6) = 951.9 KJ/kg Q_in/m dot_1 = (h_1 - h_11) + (1 - y^1) (h_4 - h_3) = 3673.6 n = 924.4 + 951/3673.6 \r\n n = 51.07% (d) Power produced: W_net = m dot_1(w dot T_1 + w dot T_2) = 20 kg/s (924.44+ 951.7) W_net = 37527 kw."