A local family sports store sells basketball. The store orders the balls from a
manufacturer at a cost of $250 per order. The annual holding cost is $6 per unit per year. The purchase price
of a basketball is $40 per unit per year. The store has a demand for
48,000 balls
per year.
The s
tock
is
received 5 working days after an order has been placed. No backorders are allowed. Assume 300 working
days a year.
a.
What is
the economic ordering quantity
? What is the optimum number of orders per year? What is the
optimal interval (in working days) between orders?
b.
What are the total annual holding costs? What are the total annual ordering costs? Using an appropriately
labelled diagram, graph setup cost, hol
ding cost, and total inventory cost, and show the economic order
quantity (EOQ) and the minimum total inventory cost.
c.
What is demand during the lead time? What is the inventory position immediately after an order has been
placed (i.e., inventory on-
hand pl
us inventory in-transit)?
d.
Suppose the store currently uses an order quantity of 1,500 balls
. Calculate the decrease in
the annual
holding cost and
the increase in the annual
ordering cost for
this policy? What would be the annual cost
saved by shifting fro
m the current 1,500 balls
order size to the EOQ order size?
e.
The store received an offer of a 5% discount from the manufacturer on orders of 3,000 or more
balls
.
Calculate the annual number of orders under the discount order quantity (DOQ). Calculate the average
inventory under the DOQ. Calculate the cost savings from the reduction in the price. Calculate the cost
savings from the reduc
ed number of orders. Calcul
ate the increase in holding costs. Calculate the net
savings from the discount? Would you recommend the store
to take the discount?
Why?
a)
EOQ = sqrt((2DS)/h) where D =48000,S = 250,h = 6
So, EOQ = sqrt((2*48000*250)/6) = 2000
What is the optimum number of orders per year?
optimum number of orders per year = Annual demand/EOQ = 48000/2000 = 24
What is the optimal interval (in working days) between orders?
optimal interval (in working days) between orders = number of working days/optimum number of orders = 300/24 = 12.5 days
b)
Total annual holding cost = (EOQ/2)*h = (2000/2)*6 = 6000
total annual ordering costs = (D/EOQ)*S = (48000/2000)*250 = 6000
EOQ is the intersection of annual ordering cost and annual holding cost
Graph data
Quantity | Annual holding cost | Annual ordering cost | ` |
400 | 1200 | 30000 | 31200 |
800 | 2400 | 15000 | 17400 |
1200 | 3600 | 10000 | 13600 |
1600 | 4800 | 7500 | 12300 |
2000 | 6000 | 6000 | 12000 |
2400 | 7200 | 5000 | 12200 |
2800 | 8400 | 4285.714286 | 12685.71429 |
c) Demand during lead time = daily demand * lead time in days = (48000/300)*5 = 800
Inventory position IP = ROP+EOQ = 800+2000 = 2800
d)
With ordreing quantity 1500, decrease in holding cost =
(2000/2)*6 - (1500/2)*6 = 1500
With ordreing quantity 1500, increase in ordering cost =
(48000/1500)*250-(48000/2000)*250 = 2000
So annual cost saved with EOQ = 2000-1500 = 1500
e)
Annual number of orders with DOQ = 48000/3000 = 16
Average inventory under DOQ = 3000/2 = 1500
Cost saving due to reduction in price = 48000*40-48000*40*0.95 =
96000
Reduction in ordering cost = (48000/2000)*250-(48000/3000)*250 = 2000
increase in holding cost = (3000/2)*6-(2000/2)*6 = 3000
Hence due to discount, net reduction is 96000+2000-3000 = 95000
Yes, the discount should be taken as total cost(purchase+ordering+holding cost) is reduced
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