ZuoTi.Pro
Question
Limiting reactant help??
Unknown number Pial Tared mass of salt mixture (g) 1003 2 209-30Bg Mass of filter paper (g) . Mass of filter paper and Ba(PO,) (g) 4. Mass of Ba,(PO)(g) . Determination of Limiting Reactant . Limiting reactant in salt mixture (write complete formula) 2. Excess reactant in salt mixture (write complete formula) ata Analysis 1. Moles of Ba,(PO, precipitated (mol) 2. Moles of limiting reactant in salt mixture (mol) Naa P04 Jodium phosphate barinnn ch10万de . formula of limiting hydrate 3. Mass of limiting reactant in salt mixture (g) formula of limiting hydrate 4. Mass of excess reactant in salt mixture (g) formula of excess hydrate 5. Percent limiting reactant in salt mixture (%) formula of limiting hydrate_ 6, Percent excess reactant in salt mixture (%) formula of excess hydrate___ *
science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

596, 939 , Taial l Taiat 2 Go g

0 0
Add a comment
Know the answer?
Add Answer to:
Limiting reactant help?? Unknown number Pial Tared mass of salt mixture (g) 1003 2 209-30Bg Mass...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • 12 Limiting reactant in salt mixture (write complete formula) Excess reactant in salt mixture (wr...

    12 Limiting reactant in salt mixture (write complete formula) Excess reactant in salt mixture (write complete formula) Analysis Moles of CCOrHO(orCC04) precipitated (mol) 0.0024 naal- 00021 Moles of CaC,o, HO (or CaC,0,) precipitated (mol) Moles of limiting reactant in salt mixture (mol) . formula of limiting hydrate eac'4 Mass of limiting reactant in salt mixture (8) Mass of excess reactant in salt mixtyre . formula of excess hydrate r C22 0 Percent limiting reactant in salt mixture (%) Percent excess...

  • i need help with data Analysis Experiment & Report Sheet Limiting Reactant Desk No. to Lab...

    i need help with data Analysis Experiment & Report Sheet Limiting Reactant Desk No. to Lab Sec. - Lab Sec. Name Precipitation of CaC,OH,O from the Salt Mixture Unknown number_ 2 I Mass of beaker() Mass of beaker and salt mixture (8) Trial Trial 2 3. Mass of salt mixture (8) 4. Mass of filter paper() 5. Mass of filter paper and product after air-dried roven-dried (e) 6. Mass of dried product() (NEE with 0.3889 0.6189 -0.280T0 Cal2o4•H2O 0.998 g...

  • Hey, i need help with the data analysis part of my HW. Thank You! Mass of...

    Hey, i need help with the data analysis part of my HW. Thank You! Mass of beaker (e) Trial I Trial 2 2 Mass of beaker and salt mixture (g) Mass of salt mixture (g) O63.9 1.2325 4 Mass of filter paper (e) 1,239 Mass of filter paper and product after air-dried oroven-dried (g) 1.S149 6Mass of dried product (g) 0.2824 252 CalaD,0 1. Formula of dried product CaCaOnHyO 0.2929 B. Determination of Limiting Reactant L. Limiting reactant in salt...

  • How do you calculate questions 1 - 8 for the data analysis section? A. Precipitation of CaC,O, H,O from the Salt...

    How do you calculate questions 1 - 8 for the data analysis section? A. Precipitation of CaC,O, H,O from the Salt Mixture Unknown number Trial 1 Trial 2 1. Mass of beaker (g) 59.45 59.45 5.oS Mass of beaker and salt mixture (g) 2. 3. Mass of salt mixture (g) I, oo oS 4. Mass of filter paper (g 5. Mass of filter paper and product after air-dried or oven-dried (g) 0, 35 6. Mass of dried product (g) 7....

  • 4. a. A sample of a CaCI 2HO/K C,0, HO solid salt mixture is dissolved in...

    4. a. A sample of a CaCI 2HO/K C,0, HO solid salt mixture is dissolved in -150 mL of deionized water previously adjusted to a pH that is basic. The precipitate, after having been filtered, was air-dried and weighed. Data for Trial I were obtained as shown. Complete the following table. (See Report Sheet.) Record calculated values with the cor- rect number of significant figures. A. Precipitation of CaC,0,H from the Calculation Zone Salt Mixture 3. Mass of salt mixture...

  • First determine the actual yield, moles of Sr3(PO4)2 formed. From the actual yield, theoretical moles of...

    First determine the actual yield, moles of Sr3(PO4)2 formed. From the actual yield, theoretical moles of limiting reactant in sample: a) Theoretical mass of limiting reactant b) Mass percent of limiting reactant in sample From the actual yield, mass of excess reactant sample, what is the mass percent of excess in sample? Beaker Sample II Unknown mixture NaPO412H2O * SrCl2* 6H2O Mass of mixture and container 113.4904g Mass of container 111.5575g Mass of mixture added to Beaker II 1.9329g Formula...

  • help with # 7 Data Table: Reactant 1 Identity_NaCO,H,O 124.00 g/mol Mass 1.02 g Reactant 2...

    help with # 7 Data Table: Reactant 1 Identity_NaCO,H,O 124.00 g/mol Mass 1.02 g Reactant 2 Identity_MnS0, H,0 169.02 g/mol Mass_1.04 g Observation of chemical reaction. Include observations about color of precipitate! Immediately after adding the two aqueous solutions together a pale pink precipitate formed. 1.49 g Mass of filter paper + precipitate Mass of filter paper Mass of precipitate (actual yield) 0.83 g 0.66 g Analysis: 1. Write the balanced chemical equation for this reaction. 2. Use a solubility...

  • UNKNOWN NUMBER Data Trial 1 Trial 2 Mass of the crucible and cover 28.2569 Mass of...

    UNKNOWN NUMBER Data Trial 1 Trial 2 Mass of the crucible and cover 28.2569 Mass of crucible, cover and sample 28.9369 2806309 30.7449 30.330g 30.328 Mass of crucible, cover and salt after first heating 29.7969 Mass of crucible, cover and salt after second heating 28.7979 Mass of crucible, cover and salt after third heating Calculations Chemical formula of anhydrous salt (given) Mass of hydrate (sample) Mass of anhydrous salt Mass of water liberated Percentage H20 in the hydrate Percentage anhydrous...

  • 4o UNKNOWN NUMBER Data Trial 2 Trial 1 ২৪.6.209 30.2449 30.3309 30 398 Mass of the crucible and cover &&.4...

    4o UNKNOWN NUMBER Data Trial 2 Trial 1 ২৪.6.209 30.2449 30.3309 30 398 Mass of the crucible and cover &&.4369 Mass of crucible, cover and sample 7989 Mass of crucible, cover and salt after first heating Mass of crucible, cover and salt after second heating &.99 Mass of crucible, cover and salt after third heating Calculations CaSOu CesOy Chemical formula of anhydrous salt (given) 21149 1.6989 9-689 Mass of hydrate (sample) Mass of anhydrous salt 04169 Mass of water liberated...

  • EXPERIMENT # 14 Assuming Na2CO, is the limiting reactant, how many grams of NaCl can be...

    EXPERIMENT # 14 Assuming Na2CO, is the limiting reactant, how many grams of NaCl can be produced from the amount of Na2CO, used in this experiment? Show calculations below: 8 Assuming HCI is the limiting reactant, how many gran of NaCl can be produced from the amount of HCI user this experiment? Show calculations below: 8 Which reactant is limiting? Which reactant is excess? 8 Actual yield of NaCl 8 Theoretical yield of NaCl % Percent yield of NaCl Show...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT