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A large steam pipe is covered with a 2.20 cm thick insulating material with a thermal conductivity of 0.27 W/(m°C). How much

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Answer #1

Thickness t = 2.20 cm = 0.022 m
Temperature inside pipe Th = 240 deg C
Temperature outside pipe Tl =27 deg C
Diameter = 2.4m
Length = 300m

Area of pipe = 2pi*rl
= pi*d*l
= pi*2.4*300
= 2261.95 m^2

Energy lost per sec = KA(Th-Tl)/t

K = 0.27 W/mC

Energy lost per sec = 0.27*2261.95*(213)/0.022

= 5.912*10^6 J/s

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