How many grams of phosphine (PH3) can form when 35.0 g of phosphorus and 96.2 L...

Question

Question

How many grams of phosphine (PH₃) can form when 35.0 g of phosphorus and 96.2 L of hydrogen gas react at STP?

P₄(s) + H₂(g) → PH₃(g) (Unbalanced)

....... g PH₃

Answer 1

Answer #1

lmole mole mole 123.88 Moles 22 Ч No dereumina whrch reagent 19 in excass and which iS limih n0 f all phosphous to ead(e nao

Answer 2

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