Question

<Homework 5 Problem 4.56 The three A-36 steel wires each have a diameter of 3 mm and the unloaded lengths of each wire are LAC = 1.80 m and LAB=LAD = 2.00 m. (Figure 1) Part A Determine the force in wire AC when the 150-kg mass is suspended from the ring at A. Express your answer to three significant figures and include appropriate units. HAO? Fac = Value Units Submit Request Answer Part B Determine the force in wire AB when the 150-kg mass is suspended from the ring at A Express your answer to three significant figures and include appropriate units. HAO? FAB = Value Units | Figure < 1 of 1 > Submit Request Answer Part C Determine the force in wire AD when the 150-kg mass is suspended from the ring at A. Express your answer to three significant figures and include appropriate units. FAD = Value Units

Answer 1

Date 0813120 That, Given Diameter of the wese (do 3 go Length of the span (LAC) = 1.8m Length of AB and AD Span (LABELAD) = 2.000 mass () - 150 kg Nowe, using the equilibrium conditione, » forly fool to I FAB=FAB Free Body daigram A Fro (315) PAS A FAR FAD Efy=0 farl ) +fect foo()= 10089.81 (90x9.81 21471SN 1 FAST FAC=14715 0 Noue, the angle en to angle ABC Length of AC a logon Length of AB - acons COSB - 1.8 De 25.84° | Nove By drawing defrsed shape of the beame, Through that we can get Sap - Soc Cos(25.84%) SAD= 0.9 SAC we know that, deflectione (8) = P2 (force (F)=P) Im 2.0 PADE all members of wires are saimetee and lame of all elasticity

SO, FADLAD=0.90(facLac). Now, Foo(2.0) -0.90ffee X1.8) » FAD=0.8) FAC fare 0-8) foc ☺ FAD-FAB By solving o&o 0 & FAB + fac=14715 FAB - Oliance 0 - we get FAB=FAD = 8400 519.126 N. I FAB= FAD= 5190126N FAC = 640.8970 Now, The Force is membee (ABG AD) - 519.126N fere is member AC -640893N,