Question

FLUID MECHANICS

Question 7

The figure below shows the top view of a sprinkler which rotates about axis c. Water leaves the sprinkler at a velocity of 48 ft/sec, relative to the tip, A in the horizontal plane in which the arms would rotate. Compute the Force, F necessary to hold the arms in place. The nozzle @ A has a 2-inch diameter, and the tangential velocity at the inner radius, Vt1 = 0.

8" 6" 200 200 12" 16"

a. 13 pounds

b. 22 pounds

c. 31 pounds

d. 44 pounds

Answer 1

488t/sec C Now in this que we will equate torque. torque = FXR NOW torque will be couple generated by Sprinkler = falvy a d=2inch. & VA = 4887 X 2 = 150.79 ft inuulge, fya 1000 x 150 2 73x)2 x 48 x12 27680 Fy = 37.65 kips Couple - FXD = 37.658 16 (kipsinal Couple due to external applied force FX12. both equal 37.65x16= F x12 F = 50.2 kips]