HW06: Problem 2 Previous Problem Problem List Next Problem (1 point) The equation бх? + Зу...
(15 points) The equation 5xy + 2x2 + 2y2 5y (*) .22 can be written in the form y' = f(y/2), i.e., it is homogeneous, so we can use the substitution u=y/2 to obtain a separable equation with dependent variable u = u(x). Introducing this substitution and using the fact that y' = ru' + u we can write (*) as y' = xu'+u = f(u) where f(u) = Separating variables we can write the equation in the form du...
The equation y' 6x2 + 3y2 ту can be written in the form y' = f(y/x), i.e., it is homogeneous, so we can use the substitution u = y/x to obtain a separable equation with dependent variable u= u(x). Introducing this substitution and using the fact that y' = ru' + u we can write (*) as y' = xu'+u = f(u) where f(u) = Separating variables we can write the equation in the form dr g(u) du = where...
(1 point) The equation z2 can be written in the form y'-f(y/z), ie., it is homogeneous, so we can use the substitution u-y/z to obtain a separable equation with dependent variable Introducing this substitution and using the fact that y' zuu we can write (*) as u u- f(u) where f(u) Separating variables we can write the equation in the form dz where g(u)- An implicit general solution with dependent variable u can be written in the form In(z) Transforming...
(1 point) The equation 3ry2r 2y2 (*) can be written in the form y f(y/x), ie., it is homogeneous, so we can use the substitution u = y/x to obtain a separable equation with dependent variable uu(x. Introducing this substitution and using the fact that y' ru' u we can write () as y xu'w = f(u) where f(u) Separating variables we can write the equation in the form da np (n)6 where g(u) = An implicit general solution with...
The equation 4zy + z² + y2 4y can be written in the form y = f(y/2). Le it is homogeneous so we can use the substitution y/z to obtain a separable equation with dependent variable u = Introducing this substitution and using the fact that y zu' + u we can write (.) as y = Du' +u = f(u) where f(u) Separating variables we can write the equation in the form dr g(u) du I where g(u) An...
4 points) Write the equation in the form y-f(u/z) then use the substitution y zu to find an implicit general solution. Then solve the initial value problem. The resulting differential equation in z and u can be written as zu' Separating variables we arrive at Separating variables and and simplifying the solution can be written in the form u2 1-Cf(x) where C is an arbitrary constant and which is separable. da du f(x) ias problem is
1 point) An equation in the form y + p(x)y -(x)y with n 0, 1 is called a Bernoulli equation and it can be solved using the substitution wich transforms the Bernoulli equation into the following first order linear equation for v: Given the Bernoulli equation we have n- We obtain the equation u' Solving the resulting first order linear equation for v we obtain the general solution (with arbitrary constant C) given by Then transforming back into the variables...
(1 point) f(az +by), ie the RHS is a inear function of z and y We wil use the substtution oaz+ by to find an impict general solution In case an equation is in the form +yo sove the initial value problem. The right hand side of the following first order problem is a linear function of az and y Use the substitution sin(a+) We obtain the following separable equation in the varables z and t 1-sin and use cos...
An equation in the form with is called a Bernoulli equation and it can be solved using the substitution which transforms the Bernoulli equation into the following first order linear equation for : Given the Bernoulli equation we have so . We obtain the equation . Solving the resulting first order linear equation for we obtain the general solution (with arbitrary constant ) given by Then transforming back into the variables and and using the initial condition to find ....
(1 point) Solve the Bernoulli initial value problem - 2 'y', y(1)=2 For this example we haven We obtain the equation + given by Solving the resulting first order linear equation for u we obtain the general solution with arbitrary constant Then transforming back into the variables 2 and y and using the initial condition to find C Finally we obtain the explicit solution of the initial value problem as