(a)
A related table with entries that are relative frequencies is formed as follows:
Busby | Dutlier | Hutchison | |
Calculator | 13/77=0.169 | 10/77=0.130 | 16/77=0.208 |
No calculator | 12/77=0.156 | 17/77=0.221 | 9/77=0.117 |
So,
Answer is:
Busby | Dutlier | Hutchison | |
Calculator | 0.169 | 0.130 | 0.208 |
No calculator | 0.156 | 0.221 | 0.117 |
(b)
P(Calculator) = 0.169 + 0.130 + 0.208 = 0.507
So,
Answer is:
0.507
(c)
P(Busby AND No calculator) = 0.156
So,
Answer is:
0.156
(d)
P(Dutlier) = 0.130 + 0.221 = 0.351
So,
Answer is:
0.351
11. 0.040.1 points Previous Answers RolfFM 7.1.013. 2/5 Submissions Used Three structors Busty, Duter, and Mrs....