Question

Calculate the amount of heat needed to boil 34.5 g of water (H2O), beginning from a temperature of 39.4 °C. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol 10

Answer 1

Heat required to heat the liquid water from 39.4℃ to 100°C: temperature change mass of water x specific heat of liquid water -34.5 gx(4184J/g"с)x(100°C-39.4°C) 8747 J Heat required to boil the liquid at 100°C: - mass of waterx heat of fusion of water 34.5 g х( 2260 J/g ) 77970 J (87473) (77970 J) = 8.67×104 J - 86.7 kJ