Question

3.) A plane is propelled by its engines at a constant 125 kilometers per hour at an angle 27 below due east. Additionally, it is carried by a wind blowing straight westward at 17.0 m/s a.) What is 125 kilometers per hour in standard SI units? (9 pts) b.) What is the net velocity vector of the plane (according to an observer in the Earth frame as a result of the sum of the two vectors? (9 pts) c.) What distance has the plane traveled in 30 minutes (according to an observer in the Earth frame)? (7 pts)

Answer 1

(a) 125 km/hr = 125 times 1000/3600 m/s = 34.72 m/s (b) V_1^vector = 34.72(cos 27 degrees i^^+ sin 27 degrees (-j^^)) V_1^vector = 30.94 i^^- 15.76 j^^V_2^vector = -17 i^^V_Net^vector = V_1^vector + V_2^vector = 30.94 i^^- 15.76 j^^- 17 i^^V_Net^vector = 13.94 i^^- 15.76 j^^(c) x^vector = V_Net^vector times t x^vector = 30 times 60(13.94 i^^- 15.76 j^^) x^vector = (25092 i^^- 28368 j^^)m x = squareroot (25092)^2 + (28368)^2 = 37872.84 m x = 37.87 km implies Distance travelled