p = 1 - 0.8 = 0.2
n = 4
This is a binomial distribution.
P(X = x) = 4Cx * 0.2x * (1 - 0.2)4-x
a) P(X = 0) = 4C0 * 0.20 * 0.84 = 0.4096 = 0.410
b) P(X > 1) = 1 - P(X = 0) = 1 - 0.4096 = 0.5904 = 0.590
c) Expected value = n * p = 4 * 0.2 = 0.8
Standard deviation = sqrt(n * p * (1 - p)) = sqrt(4 * 0.2 * 0.8) = 0.8
What is the standard deviation? (Round your answer to two decimal places.) Need Help? RodTk to...
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