Question

Use matlab to solve

Project A half-wave diode rectifier shown in the following Fig. 1 is an electrical cirouit that coeverts AC voltage to DC voltage. The voltage of the source is y,Sin(utwhere -f in whicfis the frequency. The operation of the circuit is illustrated in Fig. 2 where the dashod line shows the source veltage and the solid line shows the voltage across the resistor Diode Time Fig. 1 In the first cycle, thediode is on (conductingcurrent)fromに0umi 4Atthstme thediodetums offand the power to the resister is supplied by the discharging capacitor. Alt- ty the oode tums on again and continues lo conduct current until 1. Thecyclecontinues as longasthevoltagesourceison.11 this simplified analysis of this circuit, the diode is assumed to be idcal and the capacitor is assumed to have o charge initially (at-0).When the diode is onm, the resistor's voltage and current are given by The current in the capacitor is: cos(or) When the diode is off, the voltage across the resistor is given by The times when the diode switches off (tA D and so on) are calculated from the condtion i The diode switches on again when the volhage of the source reaches the voltage acress the resistor (time tg in the figure). Write a MATLAB program that plots the voltage across the resistor y and the voltage of the source v, as a function of time for 0 だ70 ms. The resistance ofthe load is 1,500 the voltage source 12V, andf-60 Hz. To examine the cffect of capacitor size on the voltage across the load enocute the program twice,once with C-45 uF and once with C- 10 uF

Answer 1