Question

I'm having trouble making a code for this problem, my class is working with java in while loops and for loops.

Write a method that returns true if an integer parameter n is a perfect number, false otherwise. (recall a perfect number is a number whose sum of its proper factors is equal to itself) (Precondition: n >= 1 .. means you are to presume n is positive) : EXAMPLE: 6 is a perfect number 1 2 3 equals 6 :EXAMPLE: 8 is not a perfect number... 1 2 + 4 does not equal 8 isPerfect(6) true isPerfect(8) false isPerfect(16) - false Go ..Save, Compile, Run (ctrl-enter) public boolean isPerfect(int n)

Answer 1

PerfectNumberTest.java

public class PerfectNumberTest {

public static void main(String[] args) {

PerfectNumberTest obj = new PerfectNumberTest();

System.out.println(obj.isPerfect(6));

System.out.println(obj.isPerfect(8));

System.out.println(obj.isPerfect(16));

}

public boolean isPerfect(int n) {

int sum = 0;

for (int i = 1; i <= n / 2; i++) {

if (n % i == 0) {

sum += i;

}

}

if (sum == n) {

return true;

} else {

return false;

}

}

}

Output:

true
false
false