Question

Programming In C

A)

What will print after the following statements execute?

char s1[50] = "jack";
char s2[50] = "jill";
char s3[50];
printf("%s", strcat(strcat(strcpy(s3, s1), " and "), s2));

B) What will print after the following statements execute? char s1[50] = "jack"; char s2[50] = "jill"; char s3[50]; printf("%u", strlen(s3));

Answer 1

)
char s1[50] = "jack";

char s2[50] = "jill";

char s3[50];

printf("%s", strcat(strcat(strcpy(s3, s1), " and "), s2));

After the first 3 statement three memory locations of 50*sizeof(int) space each is created namely s1,s2 and s3
Out of these 3 s1 and s2 are provided with string values "jack" and "jill" respectively
Now when the fourth statement is executed it begins by copying the value of s1 in s3
then the function stcat is called which concatenates it with the word "and" then lastly
s2 is concatenated at the end of the string thereby giving us the final output as:

jack and jill

B)
char s1[50] = "jack";
char s2[50] = "jill";
char s3[50];
printf("%u", strlen(s3));

Now the first 3 statements in B) remains the same as A)
now this time strlen function is called which is used to calculate the length of the string provided
which is s3
now %u is used which returns the value in unsigned integer
so the output printed will be:
1

Reason for the above answer is as there is no value in the character array s3 and lenght is returned in positive value so "1" is returned.

if this answer helps you please give thumbs up