Question

5 of 7 (7 complete) HW Score: 87.5%, 788 of 9 pts 8.2.18-T Assigned Media Question Help According to a survey in a country, 38% of adults do not own a credit card. Suppose a simple random sample of 800 adults is obtained Complete parts (a) through (d) below PDF (b) What is the probability that in a random sample of 800 adults, more than 42% do not own a credit card? PDF The probability is 0094 (Round to four decimal places as needed.) Interpret this probability 100 different random samples of 800 adults were obtained, one would expect 1 to result in more than 42% not owning a credit card, (Round to the nearest integer as needed.) (c) What is the probability that in a random sample of 800 adults, between 37% and 42% do not own a credit card? The probability is (Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer

Answer 1

P= 0.38 n=800 one PCI-P) ***]038 korea oy= 0.0172 we knew zosne we know a-score = pap - DCP@2042). Pizz0.42 -0.38 0.0172 PIÑ 20.43) = P(Z >2.33) P( r 30:42) = 1- P(ZK 2.3). using Z- Fable P(Z4 . 33) = 0.99011 S2 PCP 0.42) = 1-0.1901 -10.00991 op the probability is 0.00991 e i loo different random samples were obtained one would expect in more than 421. not coming a of 12 credit soo adults to result card

0 Pro.37 < P < 0.42)= P(po 2012) - P(Å 20.37) = P(ZL 0.45-0.881 _ 0.37 -0.38 0.0179 0.0172/ =P(222.3) .P (22-0.58) Using 2-table = PC222.33) = 0.9901 PCZ2-0.58), 0.2810 PC 0.37 < P L04a)a 0.9901 - 0.8810 10.7091-1 the a credit Probability of not own is 10.70911 card