Homework Answers
Given that
Mass of back pack is m= 10.0 kg
height h= 20.0 m
-------------------------------------------------
The work done by the gravity on the backpack is
W = mg (d cos(180- θ))
=- mg d cosθ
But from the above diagram d cosθ = h
W= -mgh
= -(10.0 kg)(9.80 m/s2)(20.0 m)
= -1960.0 J
The work done by hiker is simply the opposite of the work done by the gravity
Threrefore ,work done by hiker = 1960.0
Net work done = W by hiker + W by earth = 0 joules
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