C2 and C3 are in parallel
C23 = C2 + C3
C23 = 7 uF
C23 and C1 are in series
1/Ceq = 1/C23 + 1/C1
1/Ceq = 1/7 + 1/2
Ceq = 1.56 uF
charge on C1 , Q1 = Ceq*V = 1.56*50 uC = 78 uC
potential across C2 , v2 = Q1/C23
charge on Capacitor C2 , Q2 = C2*V2 = C2*Q1/C23 = 3*78/7 uC = 33.4
uC
=========================
energy stored = (1/2)*Q2^2/C2 =
(1/2)*(33.4*10^-6)^2/(3*10^-6) = 1.86*10^-4 J
In the configuration below, the battery is 50 V. Find the charge and energy stored on...
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