Question

please need help within 10min

Two wooden pucks approach each other on an ice rink as shown in the figure. Puck #2 has an initial speed of 4.18 m/s and a mass that is some fraction that of puck #1. Puck #1 is made of a hard wood and puck #2 is made of a very soft wood. As a result, when they collide, puck #1 makes a dent in puck #2 and 17.8% of the initial kinetic energy of the two pucks is lost. Before the collision, the two pucks approach each other in such a manner their momentums are of equal magnitude and opposite directions. Determine the speed of the two pucks after the collision V 4,78 V = See if you can write an expression for the total kinetic energy before the collision, the total kinetic energy after the collision, and the relationship between these two quantities, m's Puck #10 Puck #2 Additional Materials Type here to search 1145 PM A 1522019

Answer 1

Sole Given other on an ice Two wooden pucks approach each rink as shown in the figure. Puck #2 has an Initial speed of 4.18 mised' Mass that is some Fraction f = 2% Puck Y a that of puck #1 O puck a Before the in such a collisia man de puck #1 is made of a hard wood, puck #2 is made of very oft. Lost of the two pucks of the initial Kinetic Energy 17.811. e the collision, the two pucks approach each other such a manner their momentums are of Equal magni tude and opposite We have to Determine the speed of the two pucks after the collision. Collision is the event in which two or more bodies exert Forces on each other in about a relatively short time. miv, = miva V = 2/3 V2 = 2/3 (4-18) = 2.76 mire Kf = 0.822 K; By moment um Conservation, Final momentum of as a where will be zero. B = 0 = Pic " = if cos 48 ; ₂ = Vaf costo m, xVip Os 46 = ma va q los 4o » Mif = 2 / 2 % mivit + % ma vaq = (% mv, rt & m2 V 2 %) 8 0,822

minif + ma la f = 0.822 (x (2:18) + mai ( 4.18)) M gr + 2% mint = 0.822 (ox, (2.785 +2, (4.18)") Cancelled Both sides mass mi vit + 2/2 = 0.822 (1.728 + 11.648) vir + 2/3 word = 15.92 ( 23 22 t) + 2/3 vrhu = 15.92 wart (A/G + 2/3) = 15.92 Mar = 4.205 misec Then finally Waf value substituling in f = 2/(02f) Equalin MF = X (4:205) hop = 2.803 misec ) VIH = 2.803 misec V2F = 4.205 misec