It is required that a wastewater flow of 2 MGD with a strength of 300 mg/L BOD5 be treated to remove 90% of the BOD5. To achieve this, a 25-ft deep filter will be constructed and plastic media will be used. A treatability study has shown that n = 0.5 and K= 0.05 min-1 at 20⁰C. If the critical wastewater temperature is expected to be 10⁰C, what size filter should be required? Recirculation will not be used. Use Excel and Eckenfelder equation and the following steps: 1. Correct K for temp. 2. Compute acceptable hydraulic loading 3. Convert flow from MGD to gpm 4. Calculate filter surface area 5. Determine filter diameter.
It is required that a wastewater flow of 2 MGD with a strength of 300 mg/L...
Problem 5 A primary effluent with Q- 1.0 MGD, BODs 138 mg/, and SS - 104 mg/l is treated by a single stage tricking filter with the following characteristics: 6 feet deep rock trickling filter media; design BOD loading of 50 lb/day/1000 ft3; design hydraulic loading of 0.30 gpm/ft2; recirculation ratio of 1.5. Determine: 1) the volume (ft3) and diameter (ft) of the trickling filter; 2) the effluent BOD concentration. Problem 6
the design flow for a plant, using 4 tricking filters with a plastic media, is 0.5 mgd. the filters will be in parallel, the influent bod5 to filters will be 200 mg/l, the required effluent bod 5 will e 25 mg/l, the trickling filter design depth is 25 ft. lab testing conducted at 25c and 40 ft depth found the biodegradability constant to be 0.865/ft 0.5 d ^0.5. find the diameter required for each trickling filters.
\The flow rate to treat is 5.6 MGD and the BOD concentration is 150 mg/L. The design solids concentration (X) at steady-state is 2,000 mg/L. The design MCRT is 7 days. The kinetic coefficients are as follows: k = 2 g BOD/g cells*day; Ks = 25 mg BOD/L; kd = 0.06 1/day; Y = 0.5 g cells/g BOD. The influent ammonia concentration is 40 mg/L and nitrification is needed. It takes 1400 ft3 of air per pound of BOD. Use...
Question 2: (Marks 10) Wastewater with flow rate of 10,000 mº/d containing 280 mg/L of ethanolamine (C2H7NO) is to be treated by Activated Sludge Process (ASP). a) Estimate the Total Oxygen Demand (TOD) and Nitrogenous Oxygen Demand (NOD) of wastewater. b) Assuming that the COD removal rate in the aeration tank is 1.2 kg COD/mºday at 20°C, estimate the volume of the aeration tank required to achieve the effluent standard of 20 mg/L of COD.
Secondary Treatment Based on a plant flow rate of 40 mgd, design an activated sludge, secondary treatment system with recycle which maintains a MLVSS = 2,000 mg/L in the aeration reactor and has an average Solids Retention Time (SRT)-4 days. The biota kinetic constants are Kinetic Coefficients for the Activated-sludge Process for the Removal of Organic Matter from Domestic Wastewater Endogenous Decay Coefficient- k(d) 0.1 Half-velocity constant- K(s VSS/qVss-da 15 Mg/L bsCOD Max. Specific Substrate Utilization Rate-k 6 G bsCOD/gVSS-da...
Situation (note: Problem 2 is not linked with Problem 1): Assuming the design flow rate of raw wastewater to be treated is 20 MGD in the design year, the dissolved BODs is 380 mg/L, and SS is 360 mg/L. The wastewater generated by the sludge treatment process is about 4 MGD with the dissolved BODs being 1800 mg/L, and SS being 1200 mg/L, and will be returned to the wet well in the pumping station at the beginning of the...
10. Write a one-page summary of the attached paper? INTRODUCTION Many problems can develop in activated sludge operation that adversely affect effluent quality with origins in the engineering, hydraulic and microbiological components of the process. The real "heart" of the activated sludge system is the development and maintenance of a mixed microbial culture (activated sludge) that treats wastewater and which can be managed. One definition of a wastewater treatment plant operator is a "bug farmer", one who controls the aeration...