Question

HW12: Problem 2 Previous Problem Problem List Next Problem (16 points) Difficulty (375) A simply-supported beam is subjected to a coupled moment C = 480 ft-lb and the forces Fi = 300 lb and F2 = 780 lb. The dimensions of the beam are: a = 6.6 ft b= 3.7 ft c= 2.8 ft d = 3.3 ft Determine the shearing force and bending moment at the following locations. C d At x1 = 6.2 ft (from the left support) Vz1 = M21 = At 32 = 8.5 ft (from the left support) V22 = M 2 = At x3 = 10.6 ft (from the left support) V23 = M23 = At 24 = 14.7 ft (from the left support) V24 = M24 = be sure to include units with your answers

Answer 1

78016 480 + 16ooth 6.6 3.14 2.8 ft 3.37€ KA Reaction forces MA20 Re (16.4) - 780 (13-1) + 300 (103)--480 R6 = 612.1016 1 { fyzo RA TRB = 1080 st TRA = 467 3 th] TRA = 467.3 lb at a, z 6.2 ft from left support 16:27 464.316 - Vx - 46763 x 7 {fy=0 Vy = 467.3 lb Mx, = 4673(6-2) 9 M 2 289726 H- lbl s Scanned with CamScanner

(from left suna. AL = 8.5tt 450 .16 467.3 vozio vrz = 467-386 467.3(8.5) - 480 Mxz = 3492.05 lb-ft (from 10.6 ft left suppen At x2= 480 ft-16 200 lb 164. NO Vra = 667.3 - 300 (67.316 Mk3 = 467.3 (1006) - 480 – 300(0:3) osecannad 3g'3- 38 lb-++/ CamScanner

unds 14.1 JH (from lest support At 14.141 480ft-th 300 980 Ta 66 de 3.7 2.8 167 4673 Efyzo Vyu = 4673 - 300 - 180 -612lb Vry. MX2 467.3 (14.1) - 480 – 300 (4-4) - 79011.6) My = 3821.31 lb-ft rs Scanned with CamScanner