There is one mistake in your question i.e. 5/6 in the second bracket. It should be only '1'.Because my method is completly perfect.I have checked many books and google for it.I am pretty sure about the solution of this question.
3. Show that, if variations of gravity are taken into account, the time in which a...
(6 (You must show all your work). The force due to gravity on an object with mass m at a height h above the surface of the earth is _mg R F = (R+h) where is R the radius of the earth and g is the acceleration due to gravity. (a) (8 points). Express F as a series in powers of h/R. (b) (8 points). Observe that if we approximate F by the first term in the series, we get...
Question 31 (3 points) What is the force of gravity on you (m = 70kg) when you are: a) On the surface of the Earth? (1 mark) b) On the International Space Station, which is 395km above the Earth's surface? (2 marks) Some constants you may need to know: - mass of the Earth: 5.98x10^24kg - radius of the Earth: 6.38x10^6m
The Finnish sport of pesäpallo is similar to baseball with some interesting variations, one of which is that the ball is pitched vertically upward above home plate to a height of at least 1 m over the head of the pitcher and is struck by the batter as it falls toward the ground. If a pitcher releases the ball from a height of 1 m above the ground and it reaches a height of 4 m above the ground, calculate...
2. An aspiring juggler realizes that the acceleration due to gravity can be measured simply by comparing the time interval an object spends above a certain height when tossed vertically upwards to the total time it is in the air. Suppose she tosses a small ball vertically upwards and catches it a moment later (after a time ∆T elapses) at the same height it was released. In flight, the ball spends a time interval ∆t above a certain height H...
Suppose that a tank containing a certain liquid has an outlet near the bottom. Let h(t) denote the height of the liquid's surface above the outlet. Torricelli's principle states that the outflow velocity v at the outlet is equal to the velocity of a particle falling freely (with no drag) from the height h (a) Show that v2gh, where g is the acceleration due to gravity. (b) By equating the rate of outflow to the rate of change of liquid...
1. (a) Figur1 shows the forces acting on a particle that falls from rest under gravity and is subject to a retarding force proportional to its velocity, bv Figure 1 mg (0) Show that the velocity, v, as a function of time,t,can be written as 1-e m 151 (i) Determine an expression for the particle's terminal velocity. 2] 151 Find the position as a function of time. (b) The terminal velocity of the particle is 50 ms1. Find (c) (i)...
1, Humankind consumes energy at a rate of about 2 kilowatts (kW) per capita, where 1 watt (W) is 1 joule/second (J/s), with the joule being the SI unit of energy. The world population at the beginning of 2015 was about 7.22 billion people, use this value in your calculations. Estimate the world's total yearly energy consumption. 2. Space explorers land on a planet whose radius is5.30 % smaller than Earth's but whose mass is14.0 % greater than Earth's. Find...
PH 221 In Class Work 1. A particle falls with the acceleration due to gravity which has magnitude 9.8 m's At time , 0 the particle is released from rest (i.c., initial velocity ve0) at a height of 100 m from the ground. a.Make a sketch representing the initial conditions of the problem showing: i. The origin and direction of the y-axis. ii. The position of the particle at , 0. iii. The velocity of the particle at to-0. iv....
y(t) = yg +ve+-0.5gt Meteor! y = 7,000 km 1) Show that a meteor, initially at rest (V,0 = 0) will take about 20 minutes to fall from an altitude of 7,000 km as shown in the diagram to the right. Note that the change in y is negative and you will need to convert kom into meters for the units to work out correctly. y = 0 km R= 6,371 km The calculation from problem 1) is incorrect though....
A solid cone of height h and base radius r rests with its base on a surface. What is the angle with which it could be inclined on the slated sides without the cones equilibrium being disturbed. The center of gravity of the cone is at h/4 from the base.